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4x^2-4.8x-2.4=0
a = 4; b = -4.8; c = -2.4;
Δ = b2-4ac
Δ = -4.82-4·4·(-2.4)
Δ = 61.44
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.8)-\sqrt{61.44}}{2*4}=\frac{4.8-\sqrt{61.44}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.8)+\sqrt{61.44}}{2*4}=\frac{4.8+\sqrt{61.44}}{8} $
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